Question

A 12 oz. can of soda weighs about 450 grams. How many joules are released when a can of soda is cooled from 25 degrees Celsius (room temperature) to 4 degrees Celsius (the temperature of a refrigerator). The heat capacity of liquid water is 4.18 J/ gram x degrees Celsius.

Answer 1

As they don't give us data about the heat capacity of the soda, we will assume it as if it were liquid water.

To answer this question, we have to use the formula for calculation of heat.

`Q=m\cdot Cp\cdot\Delta T`

Where Q is the energy absorbed or released, m is the mass of the substance, Cp is the heat capacity and ΔT is the difference in temperature.

Replace for the given values to find Q:

`\begin{gathered} Q=450g\cdot(4.18J)/(g^(\circ)C)\cdot(4-25)^(\circ)C \\ Q=-39501J \end{gathered}`

39501 joules are released when the soda is cooled.