Question

Question 2 On a hot day a football team drank an entire 50-gallon cooler of water and half as much again. How much water did they drink? Create an equation to represent this situation.

Answer 1

`\begin{gathered} \text{Firstly they drank }\Rightarrow50\text{ gallon of water} \\ \text{Then again half of it}\Rightarrow(50)/(2)=25gallon\text{ of water} \\ So\text{, they drank} \\ \text{Drank}=50+25 \\ \text{Drank}=75\text{ gallon of water(Ans)} \end{gathered}`