Question

Electron configuration for mn+4 i really need the help i need to turn this in in like 20 minutes

Answer 1

So, we're going to find the electron configuration for the ion:

`Mn^(+4)`

This is, the same Mn electron configuration, with 4 less electrons:

`1s^22s^22p^63s^23p^64s^24p^1^{}`

As you can see, the number of electrons of the given ion is 21, so that's its electron configuration. :)