Question

Hey can you please tell me the answer of it

Answer 1

We are asked to find the perimeter of the given figure.

Recall that perimeter is the sum of all the side lengths of the figure.

First, let us find the side lengths of the figure.

Recall that the distance formula is given by

`d=√((x_2-x_1)^2+(y_2-y_1)^2)`

Let us find the width and length of the figure using the above distance formula.

`BC=√((8-4)^2+(-3-5)^2)=√(4^2+(-8)^2)=√(80)=4√(5)`

Width BC and AD are the same.

`AB=√((4-(-6)^2+(5-0)^2)=√(10^2+5^2)=√(125)=5√(5)`

Length AB and CD are the same.

So, the perimeter of the figure is

`\begin{gathered} P=2w+2l \\ P=2(4√(5))+2(5√(5)) \\ P=8√(5)+10√(5) \\ P=18√(5) \\ P=40.2 \end{gathered}`

Therefore, the perimeter of the given figure is 40.2 units.