Question

Find the equation of the line that has slope -5/9 and which passes through (-1, -7).

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Answer 1

⇒Now that you have been given the slope of the line/ the gradient of the line and a point you can easily plug in the known values in the general equation of a straight line which is y=mx+c where m is the slope and (x,y) are the given points. and c is the y-intercept

`-7=-(5)/(9) (-1)+c\\-7=(5)/(9) +c\\c=-7-(5)/(9)\\ c=-(68)/(9)`

⇒The equation of the line now is:

`y=-(5)/(9)x -(68)/(9)`

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