Question

Select the equation of the line that passes through the point(3, -1) and is parallel to the line on the graph (slope=0). (2 pcO ay = -1oby = 3cy = x-1Ody = 3x -1

Answer 1

The equation of a line that passes through the point (x1, y1) is calculated as:

`y-y_1=m(x-x_1)`

Where m is the slope and this slope should be the same slope of the line on the graph.

Since the line of the graph is a horizontal line, the slope is 0. So replacing m by 0 and (x1, y1) by (3, -1), we get:

`\begin{gathered} y-(-1)=0(x-3) \\ y+1=0 \\ y=-1 \end{gathered}`

So, the equation of the line that passes through the point(3, -1) and is parallel to the line on the graph is y = -1

Answer: y = -1