Question

** HELP ASAP!! **write an equation in slope intercept form of the line that has a slope = -3/2, and passes through the point (-3, 3)

Answer 1

Based on given conditions,

`m = - (3)/(2)`

Substitute,

`m = - (3)/(2) \\ x = - 3 \: \: \: into \\ y = 3`

So,

`y = mx + b`

`= > 3 = - (3)/(2) * ( - 3) + b`

As signs are both minus, write,

`3 = (3 * 3)/(2) + b`

`= > 3 = (9)/(2) + b`

Rearranging equations,

`= > - b = (9)/(2) - 3`

Findind LCM as 2,

`= > - b = (9)/(2) * (3 * 2)/(1 * 2)`

`= > - b = (9 - 6)/(2)`

`= > - b = (3)/(2)`

`= > b = - (3)/(2)`

Now substitute,

`m = - ( 3)/(2) \: \: \: into \\ b = - (3)/(2)`

So,

`y = mx + b`

`= > y = - (3)/(2) * x + ( - 3)/(2)`

Rewriting in slope intercept form:

(Please check attached image)

Answer 2

Given :-

• Slope of the line is -3/2 .
• It passes through (-3,3) .

To Find :-

• The equation of the line .

Solution :-

Here it's given that ,

`\longrightarrow m =(-3)/(2)`

And a point that is (-3,3) . We can use the point slope form of the line which is ,

`\longrightarrow y - y_1 = m(x - x_1)`

Substituting the respective values,

`\longrightarrow y - 3 = (-3)/(2)\{ x -(-3)\}`

Simplify,

`\longrightarrow y -3 = (-3)/(2)( x +3)`

Simplify by opening the brackets ,

`\longrightarrow y - 3 =(-3)/(2)x -(9)/(2)`

Add 3 on both sides ,

`\longrightarrow y = (-3)/(2)x -(9)/(2)+3`

Add ,

`\longrightarrow \underline{\underline{ y =(-3)/(2)x -(3)/(2)}}`

This is the required answer in slope intercept form .