Question

What is the solution to the equation below? (Round your answer to twodecimal places)5ehx=35oA X=201B = 3.980C = 4220

Answer 1

`\begin{gathered} 5\cdot\ln x=3.5 \\ \ln x^5=3.5 \end{gathered}`
`\ln x=(3.5)/(5)=.7`
`e^(.7)=x=2.01`

The answer is A, x=2.01