Question

Joey drives his car 7 km North. He stops for lunch and then drives 5 km south. What is his total displacement?

Answer 1

Given

7 km north

5 km east

Procedure

The displacement is simply the difference in the position of the two marks and is independent of the path taken when traveling between the two marks.

`\begin{gathered} d=\sqrt[]{5^2^{}+7^2} \\ d=\sqrt[]{74} \\ d=8.60\text{ km} \end{gathered}`