Question

A 2.5L sealed flask is filled with gas at 780 atm and 273K. What is the temperature of the gas in Celcius at 851atm if the volume is constant?

Answer 1

297.85 K.

Explanation:

What is given?

Pressure 1 (P1) = 780 atm.

Pressure 2 (P2) = 851 atm.

Temperature 1 (T1) = 273 K.

Constant volume = 2.5 L.

What do we need? Temperature 2 (T2).

Step-by-step solution:

To solve this type of problem, when the volume is constant, but pressure and volume vary, we use Gay-Lusscac's Law. Gay-Lussac's law states that the pressure of a constant volume of a gas is directly proportional to its temperature. The formula of this law will look like this:

`(P_1)/(T_1)=(P_2)/(T_2).`

And finally, we have to solve for Temperature 2, which is T2, and replace the given data:

`\begin{gathered} T_2=(T_1P_2)/(P_1), \\ T_2=\frac{273\text{ K}\cdot851\text{ atm}}{780\text{ atm}}, \\ T_2=297.85\text{ K.} \end{gathered}`

The final temperature would be 297.85 K.