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Consider the circle below
{x}^(2) + {y}^(2) - 22x + 24y - 9 = 112Find the center and radius.

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\begin{gathered} \text{ x}^2+y^2\text{ - 22x + 24y - 9 = 112} \\ \text{ x}^2-22x+y^2\text{ + 24y = 112 + 9} \\ x^2-22x+(11)^2+y^2+24y+(12)^2\text{ = 121 + 121 + 144} \\ (x-11)^2+(y+12)^2\text{ = 386} \\ \end{gathered}

Center = (11, -12)


\text{Radius = }\sqrt[]{386}

answered
User Tom Nolan
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