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Suppose a 9 kg block Of metal is held fully underwater. the metal block has a volume of 0.008 m^3 . water has a weight density of 9800 N/m^3 . will the block sink or float, if it is let go?A) it will sink B) it will float C) It will remain suspended in the waterD) Not enough information to determine

1 Answer

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Given:

The mass of the block is


m=9\text{ kg}

The block is held fully underwater.

The weight density of water is,


dg=9800\text{ N/m}^3

To find:

The block will sink or float

Step-by-step explanation:

The buoyant force on the block is,


\begin{gathered} F_B=Vdg \\ =0.008*9800 \\ =78.4\text{ N} \end{gathered}

The weight of the block is,


\begin{gathered} W=mg \\ =9*9.8 \\ =88.2\text{ N} \end{gathered}

Here, we see that the weight of the block is greater than the buoyant force given by the water which is the downward force is greater than the upward buoyant force.

Hence, the block will sink.

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User Thegreenogre
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