Question

An object is 12.0 cm from aconcave mirror with f = 18.0 cm.Find the magnification.(Mind your minus signs.)(Unit = cm)

Answer 1

Answer:

Magnification = 3

Step-by-step explanation:

Given:

Object distance = 12.0 cm

Focal length, f = 18.0 cm

The image distance, v = ?

`\begin{gathered} (1)/(f)=(1)/(u)+(1)/(v) \\ \\ (1)/(18)=(1)/(12)+(1)/(v) \\ \\ (1)/(v)=(1)/(18)-(1)/(12) \\ \\ (1)/(v)=-0.02777777777 \\ \\ v=-(1)/(0.02777777777) \\ \\ v=-36 \\ \\ \\ \end{gathered}`

The magnification, M, is calculated as:

`\begin{gathered} M=|(v)/(u)| \\ \\ M=|-(36)/(12)| \\ \\ M=|-3| \\ \\ M=3 \end{gathered}`