Question

How many grams of Ag will be produced from 3.65 moles of silver nitrate?

Answer 1

E¹= Equivalent mass of Cu= 31.77

E²= Equivalent mass of Ag= 108

Weight of Cu deposited = 3.5

So Wt.of Ag deposited =3.5x(108/31.77) = 11.898 g

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Answer 2

3.65

Step-by-step explanation:

In Picture Below