Question

What is the solution to the equation below? 2х 、 x -2 O A. X= 3 O B. x=6 C. X= 4 D. X= 5

Answer 1

The given equation is

`\frac{\sqrt[]{2x}}{\sqrt[]{x-2}}=2`

We will square both sides to cancel the roots

`\frac{(\sqrt[]{2x})^2}{(\sqrt[]{x-2)^2}}=(2)^2`

Power 2 will cancel the square roots on the left side

`(2x)/(x-2)=4`

By using cross multiplication