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How many possible values are there for x in the equation?X2 = 36/81

How many possible values are there for x in the equation?X2 = 36/81-example-1
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User Arbuzov
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1 Answer

3 votes

It is given that


\begin{gathered} x^2=(36)/(81) \\ x=\sqrt[]{(36)/(81)} \\ x=\pm(6)/(9) \end{gathered}

So there are two possible values of x .

Hence the correct option is b) two values

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User Xargs
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