Question

If f(x) = - 3x + x2 - 6x2 +9, then f(x)=1 as x-infinity, and f(x) as x-infinity.

Answer 1

`\begin{gathered} f(x)=-3x^5+x^3-6x^2+9 \\ \text{Let's take the limits} \\ \lim _(x\to-\infty)f(x)=\lim _(x\to\infty)-3x^5=(-3)(-\infty)=\infty \end{gathered}`
`\lim _(x\to\infty)-3x^5=(-3)(\infty)=-\infty`