Question

Write the base dissociation constant (Kb) equation.

Answer 1

When a base (BOH) disociates in water the following equilibrium takes place:

`BOH\rightleftarrows OH^-+B^+`

Then the base dissociation constant (Kb) is expressed as:

`Kb=([OH^-][B^+])/([BOH])`

It is the product of the concentration of the products devided by the concentration of the reactant