Question

5. Find the length of a rectangle whose width is 4xy and whose area is16xy² + 24x²y.a. 10xyb. 4y + 6xc. 12y + 20xd. 24xye. 10y + 10x

Answer 1

The area of a rectangle is:

`Area=length*width`

Solve length in the equation above:

`length=(Area)/(width)`

Use the given information to find the length:

`\begin{gathered} length=(16xy^2+24x^2y)/(4xy) \\ \\ length=(xy(16y+24x))/(4xy) \\ \\ length=(16y+24x)/(4) \\ \\ length=(16)/(4)y+(24)/(4)x \\ \\ length=4y+6x \end{gathered}`

Then, the length of the rectangle is 4y+6x

Answer: b.