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5 votes
Use even or odd properties of the trigonometric function to find the exact value of the expression.
tan ( - (\pi)/(6) )

asked
User Orrymr
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1 Answer

4 votes

We can rewrite the expression as following:


\tan (-(\pi)/(6))=(\sin(-(\pi)/(6)))/(\cos(-(\pi)/(6)))

Since sine is odd, and cosine is even,


(\sin(-(\pi)/(6)))/(\cos(-(\pi)/(6)))\rightarrow(-\sin((\pi)/(6)))/(\cos((\pi)/(6)))\rightarrow-(\sin((\pi)/(6)))/(\cos((\pi)/(6)))

Evaluating both trigonometric functions,


-(\sin((\pi)/(6)))/(\cos((\pi)/(6)))=-\frac{(1)/(2)}{\frac{\sqrt[]{3}}{2}}\rightarrow-\frac{2}{2\sqrt[\square]{3}}\rightarrow-\frac{2\sqrt[\square]{3}}{6}\rightarrow-\frac{\sqrt[]{3}}{3}

Thereby,


\tan (-(\pi)/(6))=-\frac{\sqrt[]{3}}{3}

answered
User Irosenb
by
8.0k points

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