Question

3MgCl2 + 2Al → 3Mg + 2AlCl3If 4.9 grams of MgCl2 reacted how many grams of AlCl3 are produced?

Answer 1

So, to find the amount of AlCl3 produced, we could write the following:

`4.9\text{gMgCl}2\cdot\frac{1\text{molMgCl}2}{95.2\text{gMgCl}2}\cdot\frac{2\text{molesAlCl3}}{3\text{molesMgCl}2}\cdot\frac{133.34gAlCl3}{1\text{molAlCl}3}=4.57539gAlCl3`

Therefore, there are 4.57539 grams of AlCl3 produced.