Question

3. A force of 380 N is applied to a 38 kg object over a distance of 2.5 meters. What is the speedof the object after it accelerates?

Answer 1

Given,

Force, F = 380 N

Mass, M = 38 kg

Distance, d = 2.5 m

The work done on the body is equal to the final kinetic energy.

`F* d=(1)/(2)mv^2`

Put the given values in the formula,

`\begin{gathered} 380\text{ N}*2.5\text{ m = }(1)/(2)*38kg* v^2 \\ v^2=(950*2)/(38) \\ v^2=50 \\ v=\sqrt[]{50} \end{gathered}`

Thus, the speed of the object after it accelerates is

`v=7.07\text{ m/s}`