Question

Enterrange of values for x.a(+2) 37°1314[?]

Answer 1

It's important to know that the acute angles shown are not equal because their opposite sides are different 13 and 14, respectively.

Following this relation, we can deduct that the angle x+2 should be less than 37 because 13<14.

`x+2<37`

Subtract 2 from both sides.

`\begin{gathered} x+2-2<37-2 \\ x<35 \end{gathered}`

This means that the values of x must be less than 35.

On the other hand, the angle x+2 must be greater than zero, otherwise, it wouldn't make any sense.

`x+2>0`

Subtract 2 from both sides.

`\begin{gathered} x+2-2>0-2 \\ x>-2 \end{gathered}`

This means the values of x must be greater than -2.

Then, we unite both intervales to make one.

[tex]-2This interval means that the values of x must be between -2 and 35.