Question

The question is how do the impulses applied to the two balls compare?

Answer 1

Given data:

* The force applied on the ball is F = 900 N.

* The time of contact between Bob and the ball is t_1 = 0.3 s.

* The time of contact between Jill and the ball is t_2 = 0.6 s.

Solution:

The impulse applied by the bob is,

`\begin{gathered} J_1=Ft_1 \\ J_1=900*0.3 \\ J_1=270\text{ kgm/s} \end{gathered}`

The impulse applied by Jill is,

`\begin{gathered} J_2=Ft_2 \\ J_2=900*0.6 \\ J_2=540\text{ kgm/s} \end{gathered}`

Thus, the impulse applied by Jill is more than the impulse applied by Bob.

Hence, 4th option is the correct answer.