Question

Find the sum of the first 10 terms of the following series, to the nearest integer.24,96,384, ...

Answer 1

`s\text{ }=\frac{a(r^n-1)^{}}{r-1}`

a = 24

n= 10

r = 96/24 = 4

Replacing:

`s=(24(4^(10)-1))/(4-1)=(24\cdot1,048,575)/(3)`

s = 8,388,600