asked 103k views
4 votes
I need help on a question

asked
User Luuklag
by
8.3k points

1 Answer

3 votes

Solution

For this case we can do the following:


8^2=x^2+y^2

And we can create the following two questions:


2^2+z^2=x^2,6^2+z^2=y^2

If we subtract the last two equations we got:


6^2-2^2=y^2-x^2

Solving for y^2 we got:


y^2=36-4+x^2=32+x^2

Replacing we got in the first equation:


8^2=x^2+32+x^2

And solving for x we got:


64-32=2x^2
32=2x^2
16=x^2
x=\sqrt[]{16}=4

answered
User Trishulpani
by
8.4k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.