Question

A number from 15 to 23 is drawn at random p(a number divisable by 3)

Answer 1

Given:

`\begin{gathered} Sample\text{ space}=\lbrace15,16,17,18,19,20,21,22,23\rbrace \\ Total\text{ n}umber\text{ of possible outcomes}=9 \\ \\ \\ Numbers\text{ divisible by 3}=\lbrace15,18,21\rbrace \\ Number\text{ of required outcome}=3 \end{gathered}`

Therefore, the probability of picking a number divisible by 3 is;

`\begin{gathered} P(a\text{ number divisible by 3\rparen}=(3)/(9) \\ \\ Simplifying\text{ further,} \\ P(a\text{ number divisible by 3\rparen}=(1)/(3) \end{gathered}`