Question

if a stone dropped into a well reaches the water surface after 3.0 seconds, how far did the stone drop before hitting the waterA. 1.4 metersB. 44 metersC. 49 metersD. 54.2 meters

Answer 1

Given data:

Time taken by the stone before hitting the water;

`t=3.0\text{ s}`

Initial velocity of the stone;

`u=0`

The distance covered by the stone before hitting the water is given as,

`s=ut+(1)/(2)gt^2`

Here, g is the acceleration due to gravity.

Substituting all known values,

`\begin{gathered} s=(0)*(3\text{ s})+(1)/(2)*(9.8\text{ m/s})*(3\text{ s})^2 \\ =44.1\text{ m} \\ \approx44\text{ m} \end{gathered}`

Therefore, the stone travelled a distance of 44 meters before hitting the wat