Question

1. If the perimeter of a rectangle measures 50 feet and the length of the rectangle is 17 feet, what is the width?32 feet8 feet16 feetcannot be determined; not enough information

Answer 1

8 feet

Step-by-step explanation:

The perimeter of a rectangle = 2(Length + Width)

Given:

• Perimeter = 50 feet

,

• Length = 17 feet

We substitute these into the formula above:

`50=2(17+\text{Width)}`

We then solve for the width.

`\begin{gathered} (50)/(2)=\frac{2(17+\text{Width)}}{2} \\ 25=17+\text{Width} \\ \text{Width}=25-17 \\ \text{Width = 8 feet} \end{gathered}`

The width of the rectangle is 8 feet.