Question

Determine the range of y=√x/√x+2

Answer 1

`y=\frac{\sqrt[]{x}}{\sqrt[]{x+2}}`

For this case we can do the following:

`y=\sqrt[]{(x)/(x+2)}`

The minimum value should be 0 for y assuming that x>= 0

Then the range should be:

`0\le y<1`