The figure is composed of a rectangle with a base of 10 mm and a height of 9 mm, and a triangle with a base of 14 - 10 = 4 mm and a height of 9 - 3 = 6 mm.
The area of the rectangle is calculated as follows:
![\begin{gathered} A=\text{base}\cdot\text{height} \\ A_1=10\cdot9=90\operatorname{mm}^2 \end{gathered}]()
The area of the triangle is calculated as follows:
![\begin{gathered} A=\text{base}\cdot\text{height}\cdot(1)/(2) \\ A_2=4\cdot6\cdot(1)/(2)=12\operatorname{mm}^2 \end{gathered}]()
Therefore, the total area is
![A_1+A_2=90+12=102\operatorname{mm}^2]()