Question

A net of a square pyramid as shown what is the surface area in square inches of a pyramid

Answer 1

We are asked to determine the surface area of the pyramid. To do that we will add the area of each of the faces. First, we will add the area of the triangular faces. The area of a triangle is given by:

`A_t=(bh)/(2)`

Where "b" is the base and "h" is the height.

The height is given as 6in and the base is 5in. Therefore, the area is:

`A_t=((5in)(6in))/(2)`

Solving the operations:

`A_t=15in^2`

Now, we determine the area of the square. The area of a square in the square of its length, therefore, we have:

`A_s=(5in)^2`

Solving the operations:

`A_s=25in^2`

Now, we add the areas. We need to have into account that there are 4 triangles therefore, we need to multiply the triangular area by 4:

`A=4A_t+A_s`

Substituting the values we get:

`A=4(15in^2)+25in^2`

Now, we solve the operations:

`A=85in^2`

Therefore, the surface area is 85 square inches.