Question

Factor each polynomial using the difference of two perfect squares

Answer 1

Number 5

So for the difference of perfect squares factor with the numbers on both factors having to be the same, but one adds and one subtracts.

`m^2-(1)/(9)`
`\begin{gathered} \text{The formula is} \\ a^2-b^2=(a+b)(a-b)_{} \end{gathered}`

`m^2-(1)/(9)=(m+(1)/(3))(m-(1)/(3))`