Question

TRIGONOMETRY What is the magnitude of c round to the nearest hundredth

Answer 1

19.72

Explanation:

To calculate the magnitude of the vector, we must apply the norm to its coordinates.

That is, its magnitude is equal to the square root of the sum between the squares of its value at x and its value at y.

Therefore:

`v=√(\left(v_x\right)^2+\left(v_y\right)^2)`

We replacing:

`\begin{gathered} v=√(\left(10\right)^2+\left(17\right)^2) \\ v=\sqrt[]{100+289} \\ v=\sqrt[]{389} \\ v=19.72 \end{gathered}`

The magnitude of the vector is 19.72