Question

The cubic expansivity of mercury is 1.8×10^-4K^-1 and the linear expansivity of glass is 8.0×10^-6K^-1, calculate the apparent expansivity of mercury in a glass container?

Answer 1

`\begin{gathered} \text{cubic expansivity of mercury=1.8}*10^(-4)K^(-1) \\ \text{ Linear expansivity of glass = 8.0}*10^(-6)K^(-1) \end{gathered}`

Therefore,

`Apparent\text{ cubic expansivity=}real\text{ cubic expansivity - cubic expansivity of the container}`
`\begin{gathered} \text{ cubic expansivity of the container =3(}8.0*10^(-6))=24*10^(-6)=2.4*10^(-5) \\ \text{note we converted linear expansivity to cubic expansivity} \end{gathered}`

Finally,

`\text{Apparent cubic expansivity=}1.8*10^(-4)-2.4*10^(-5)=1.56*10^(-4)K^(-1)`