Question

Please find the distance between the two points (6,-3) (3,1)

Answer 1

We use the formul for the distance between any two points (x1, y1) and (x2, y2) on the plane:

distance = square root ((y2- y1)^2+ (x2 - x1)^2)

I equation form for our case it is:

`\begin{gathered} \text{distance}=\sqrt[]{(y2-y1)^2+(x2-x1)^2} \\ \text{distance}=\sqrt[]{(-3-1)^2+(6-3)^2} \\ \text{distance}=\sqrt[]{16+9} \\ \text{distance}=\sqrt[]{25} \\ dis\tan ce=5 \\ \end{gathered}`

Therefore in our case tha distance becomes the square root of 25 whci is "5".