Question

Please just answer question 11

Answer 1

I hope this helps you :)

Answer 2

• 
  `\mathrm{No\:Solution}`

Explanation:

• given that:
  `(p^2 +1)x^2 +2pqx+q^2 = 0`
• also its being said that: it has no solution
• thus shall we use the formula: b²-4ac < 0

Extra's:

• when it has solution: b²-4ac > 0
• when has only one or equal use: b²-4ac = 0
• when it has no solution or real numbers: b²-4ac < 0

Now lets solve:

`(p^2 +1)x^2 +2pqx+q^2 = 0`

`(p^2 +1)x^2 +(2pq)x+q^2 = 0`

using b²-4ac < 0:

`(2pq)^2 - 4 * (p^2 +1 )(q^2 ) <0`

`4p^2 q^2 - 4p^2q^2 -4q^2<0`

`-4q^2 < 0`

`\mathrm{No\:Solution\:for}\:p\in \mathbb{R}`