Question

Find the diameter of a circle with an area of 240.25 square millimeters.

Answer 1

Given a circle with radius, r, the area, A, is given by

`\begin{gathered} A=\pi* r^2 \\ \text{where }\pi\approx3.14 \end{gathered}`

In this case,

A = 240.25 square millimeters

Hence, we have

`\begin{gathered} \pi* r^2=240.25 \\ \text{ Which implies that} \\ 3.14r^2=240.25 \end{gathered}`

That is

`\begin{gathered} r^2=(240.25)/(3.14) \\ r\text{ = }\sqrt[]{(240.25)/(3.14)} \end{gathered}`

The diameter of a circle = 2 x radius

Therefore,

`\text{ Diameter = }2*\text{ }\sqrt[]{(240.25)/(3.14)}\approx17.49\text{millimeters}`