Solve for d if d=√(2(x2 - x1)2 + 4(y2 - y1)2)if x1=4 y1=5 x2=8 y2=16

Question

Solve for d if d=
`√(2(x2 - x1)2 + 4(y2 - y1)2)`if x1=4 y1=5 x2=8 y2=16

Answer 1

Using the given values in the equation and calculating the value of D, we have:

`\begin{gathered} D=\sqrt[]{2(x_2-x_1)^2+4(y_2-y_1)^2} \\ D=\sqrt[]{2(8-4)^2+4(16-5)^2} \\ D=\sqrt[]{2\cdot4^2+4\cdot11^2} \\ D=\sqrt[]{2\cdot16+4\cdot121} \\ D=\sqrt[]{32+484} \\ D=\sqrt[]{516} \\ D=22.7156 \end{gathered}`