Question

Find the values of x for which the curve has horizontal tangents

Answer 1

N 7

we have

`y=x^3-2x^2+x+1`

step 1

Find out the first derivative

`y^(\prime)=3x^2-4x+1`

step 2

Equate the first derivative to zero

`3x^2-4x+1=0`

Solve the quadratic function

the solutions are

x=1/3 and x=1