Question

Write y=-2(x+4)^2+2 in standard form please and show work

Answer 1

The standard form a quadratic function is given by:

`y=ax^2+bx+c`

then, we need to expand the parenthesis. This can be give as

`(x+4)^2=x^2+8x+16`

By substituting this result into our expression, we have

`y=-2(x^2+8x+16)+2`

By distributing the parenthesis, we have

`y=-2x^2-16x-32+2`

then, the answer is

`y=-2x^2-16x-30`