Question

24. An elevator is moving vertically up with an acceleration a. The force exerted on the floor by a passenger of mass m is

(a) mg (b) ma (c) mg - ma (e) none of these (d) mg + ma​

Answer 1

Given :-

• An elevator is moving vertically up with an acceleration a.

To Find :-

• The force exerted on the floor by a passenger of mass m .

Solution :-

As the man is in a accelerated frame that is non inertial frame , we would have to think of a pseudo force .

• The direction of this force is opposite to the direction of acceleration the frame and its magnitude is equal to the product of mass of the concerned body with the acceleration of the frame .

For the FBD refer to the attachment . From that ,

`\implies Weight_(apparent)= mg + ma`

Hence option d is correct choice .

I hope this helps .