Question

What pressure (in atmospheres) is exerted by 0.300 moles of Xenon gas in a 2.53 L container at 290.0 K?2.822.322.632.40

Answer 1

The pressure of the gas is 2.82 atm

Step-by-step explanation

Given that;

The moles of the gas is 0.30 moles

The volume of the gas is 2.53L

The temperature of the gas is 290K

Follow the steps below to find the pressure of the gas

Assume is the gas behaves like an ideal gas

`\text{ PV = nRT}`

Substitute the given data into the formula above

`\begin{gathered} \text{ Recall, that the universal gas constant is 0.08205 L. atm . mol}^(-1).\text{ K}^(-1) \\ \text{ P }*\text{ 2.53 = 0.3 }*\text{ 290}*\text{ 0.08205} \\ \text{ 2.53P = 7.13835} \\ \text{ Divide both sides by 2.53} \\ \text{ P = }\frac{\text{ 7.13835}}{\text{ 2.53}} \\ \text{ P = 2.82 atm} \end{gathered}`

Therefore, the pressure of the gas is 2.82 atm