Question

let g( x)be a vertical stretch by a factor of 2 and a horizontal translation 3 to the left of f (x )= x ^ 5 + 3x .write a rule for g( x )

Answer 1

Let us first do the stretch factor of 2

`2x^5+6x`

and then, we have to translate 3 units to the left

`2(x+3)^5+6(x+3)`

So we get that

`g(x)=2(x+3)^5+6(x+3)`