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What is the diameter of a sphere with a volume of 80487 in^3, to the nearest tenth ofan inch?

What is the diameter of a sphere with a volume of 80487 in^3, to the nearest tenth-example-1
asked
User Lomaxx
by
8.3k points

1 Answer

3 votes

EXPLANATION

If the volume of a sphere is 80487 in^3, the diameter would be given by the following relationship:


\text{Volume}=(4)/(3)\cdot\pi\cdot r^3

Replacing terms:


80487=(4)/(3)\cdot\pi\cdot r^3

Isolating r^3:


(80487)/(\pi)\cdot(3)/(4)=r^3

Applying the cubic root to both sides:


\sqrt[]{(80487)/(\pi)\cdot(3)/(4)}=r

Switching sides:


r=\sqrt[]{(80487)/(\pi)\cdot(3)/(4)}

Multiplying numbers:


undefined

answered
User Jovylle
by
8.0k points
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