Question

Find the value of x. Round to thenearest tenth.1.41ft2.1 ft= [?] ft

Answer 1

From the given figure, x should be twice the missing side of the triangle formed.

We get,

`\text{ x = 2}\sqrt[]{2.1^2-1.4^2}`
`\text{ x = 2}\sqrt[]{4.41-1.96^{}}`
`\text{ = 2}\sqrt[]{2.45^{}}`
`\text{ = }3.130495168499706‬\text{ }\approx\text{ 3.1}`
`\text{ x = 3.1 ft.}`

Therefore, x = 3.1 ft.