Question

Solve sin2x-sin4x +sin6x=0

Answer 1

Remember that

`\sin 2\theta=2\sin \theta\cos \theta`

Therefore,

`\begin{gathered} \sin 2x-\sin 4x+\sin 6x=0 \\ \Rightarrow2\sin x\cos x-2\sin 2x\cos 2x+2\sin 3x\cos 3x=0 \end{gathered}`

Then,