Question

On a standardized exam, the scores are normally distributed with a mean of27 and a standard deviation of 4. Find the Z-score of a person who scored 17on the exam.

Answer 1

mean = 27

standard deviation = 4

n = 17

z = ?

`\begin{gathered} \text{ z = }\frac{X\text{ - }\mu}{\sigma} \\ \text{ z = }\frac{27\text{ - 17}}{4} \\ \text{ z = }(10)/(4) \\ \text{ z = 2.5} \end{gathered}`

Result :

z = 2.5