Question

B. 9m2 + 6m + 6 = 5 has real roots and imaginary roots

Answer 1

the given equation is

`\begin{gathered} 9m^2+6m+6=5 \\ 9m^2+6m+1=0 \end{gathered}`

we will calculate

`D=b^2-4ac`

so

`\begin{gathered} =6^2-4*9*1 \\ =36-36 \\ =0 \end{gathered}`

as D is 0 so it has one real root