Question

Jason is pulling a box across the roompulling with a force of 16 newtons and his arm is making a 68 anglet with the horizontal what is the horizontal component of the he is pulling with?

Answer 1

The horizontal component of a force is defined as follows

`F_x=F\cdot\cos \theta`

Where F = 16 N, and theta = 68. Let's use these values to find the horizontal component of F.

`F_x=16N\cdot\cos 68\approx6N`

Therefore, the horizontal component of the pulling force is 6 Newtons.